x^2+22x-3600=0

Solution for x^2+22x-3600=0 equation:

X^2+22X-3600=0

a = 1; b = 22; c = -3600;
Δ = b2-4ac
Δ = 222-4·1·(-3600)
Δ = 14884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14884}=122$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-122}{2*1}=\frac{-144}{2}
=-72
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+122}{2*1}=\frac{100}{2}
=50
$